3[x+1]=4x-x+3

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Solution for 3[x+1]=4x-x+3 equation:


Simplifying
3[x + 1] = 4x + -1x + 3

Reorder the terms:
3[1 + x] = 4x + -1x + 3
[1 * 3 + x * 3] = 4x + -1x + 3
[3 + 3x] = 4x + -1x + 3

Reorder the terms:
3 + 3x = 3 + 4x + -1x

Combine like terms: 4x + -1x = 3x
3 + 3x = 3 + 3x

Add '-3' to each side of the equation.
3 + -3 + 3x = 3 + -3 + 3x

Combine like terms: 3 + -3 = 0
0 + 3x = 3 + -3 + 3x
3x = 3 + -3 + 3x

Combine like terms: 3 + -3 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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